If one zero of the quadratic polynomial 4x2-8kx-9 is the negative of the other.Find the value of k
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Answer :-
→ k = 0 . ---
Step-by-step explanation :-
It is given that,
→ One zeros of the given polynomial is negative of the other .
Let one zero of the given polynomial be x .
Then, the other zero is -x .
•°• Sum of zeros = x + ( - x ) = 0 .
But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .
==> 2k = 0 .
==> k = 0/2 .
•°• k = 0 .
Hence, it is solved.
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