If one zero of the quadratic polynomial ax2 +
bx + ci s cube of the other then the value of
the sum of the cubes of both the zeroes is
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Let α,β be the other zeros of the given polynomial x3+ax2+bx2+c
Sum of the zeros =coefficient of x3−coefficient of x2
⇒−1+α+β=1−a=−a
⇒α+β=−a+1 (i)
Again,
(−1)α+αβ+(−1)β=coefficient of x3−coefficient of x
⇒−α+αβ−β=1b
=αβ=b+α+β
α+β=−a+1 , from (i))
=b−a+1
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