Question

if one zero of the quadratic polynomial
f(x) = 2x³-3kx²+4x-5 is 6 ,then the value of k is​

Answer 1

The sum of the zeroes of the equation ax3+bx2+cx+d is −b/a

Here the equation is 2x3−3kx2+4x−5

⇒ Sum of roots=3k/2

⇒ 3k/2=6

⇒ k=4

Therefore,Option B is correct.

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