If one zero of the quadratic polynomial f(x) = 4x^2-8kx-9 is negative of the other, then find the value of k?
Answers
Answered by
4
Let the zeroes be a and -a.
So,
a + ( - a) = - b / a = 8k / 4
0 = 2k
k = 0
Answered by
7
Answer:
Comparing f(x) = 4x2 - 8kx - 9 with ax2+bx+c we get
a=4; b=-8k and c=-9.
Since one root is the negative of the other, let us assume that the roots are p an -p.
Sum of the roots, a+(-a)=-b/a=-(-8k)/4
0=2k
k=0
Step-by-step explanation:
hope it helps u
please mark it as brainlist
Similar questions