Question

If one zero of the quadratic polynomial f(x)=4x^2-8kx-9 is -ve of the other find the value of k

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Answer :-

→ k = 0 .

Step-by-step explanation :- -----

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

•°• k = 0 .

Hence, it is solved.