Question

If one zero of the quadratic polynomial f(x) =4x^2-8kx-9is negative of the other, then find the value of k

Answer 1

4x²-8kx-9

Let the zero be a & -a

Sum of zero =-b/a
a+(-a) =-(-8)k/4

a-a=8k/4

0=2k

0/2=k


0=k

So, the value of k=0

Answer 2

Step-by-step explanation:

Answer :-

→ k = 0 . --------

Step-by-step explanation :-

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

•°• k = 0 .

Hence, it is solved.