if one zero of the quadratic polynomial f(x) = 4x²-8kx-9 is negative of the other,find the value of k
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Let the zeroes of the polynomial be α and -α.
Then, sum of zeroes = -b/a.
》-α+α= -(-8k)/4
》0= 8k/4
》8k= 0
》k= 0
The value of k is 0.
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Answered by
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Answer :- -----;;-;;;;
→ k = 0 .
Step-by-step explanation :-
It is given that,
→ One zeros of the given polynomial is negative of the other .
Let one zero of the given polynomial be x .
Then, the other zero is -x .
•°• Sum of zeros = x + ( - x ) = 0 .
But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .
==> 2k = 0 .
==> k = 0/2 .
•°• k = 0 .
Hence, it is solved.
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