if one zero of the quadratic polynomial f(x)=4x2-8kx-9 is negative of the other find the value of k
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Sol :
Let x be zero of the quadratic polynomial then -x is negative of the other.
∴ f(x) = f(-x)
Given f{x}=x2-8kx-9
x2-8kx-9 = x2+8kx-9
-8kx = 8kx
∴ k = 0 .
Let x be zero of the quadratic polynomial then -x is negative of the other.
∴ f(x) = f(-x)
Given f{x}=x2-8kx-9
x2-8kx-9 = x2+8kx-9
-8kx = 8kx
∴ k = 0 .
BhavyamThakur:
Thanku very much
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Step-by-step explanation:
Answer :-
→ k = 0 .
Step-by-step explanation :-
It is given that,
→ One zeros of the given polynomial is negative of the other .
Let one zero of the given polynomial be x .
Then, the other zero is -x .
•°• Sum of zeros = x + ( - x ) = 0 .
But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .
==> 2k = 0 .
==> k = 0/2 .
•°• k = 0 .
Hence, it is solved.
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