Question

If one zero of the quadratic polynomial g(x) = (k + 1)x^2– 5x + 5 is multiplicative

Inverse of the other, then find the zeroes of kx^2– 3kx + 9.

Answer 1

Answer:

h ena HANSNJSJJSJJS janjati Nsbsjsjshhsh

Answer 2

Answer:

3/2, 3/2

Step-by-step explanation:

given polynomial= g(x)..........(1)

since one zero is multiplicative inverse of other.

let alfa and beta are zeroes.

=> alfa× beta= 1

=> 5/ (k+1)= 1 => k+1= 5 => k = 4

again

putting the value of k in kx²-3kx+9

=> 4x²-12x+9

= 4x²-6x-6x+9

= 2x ( 2x-3) - 3( 2x-3)

=( 2x-3) ( 2x-3)

thus x= 3/2

both zeroes are equal= 3/2