Question

If one zero of the quadratic polynomial is given and find the value of k

Answer 1

Step-by-step explanation:

Hey!

Given polynomial :- p ( x ) = x² + 4kx - 25

Let first Zero be a and second zero be -a ( it is given that one root is negative of other )

• Sum of zeros =

= \frac{ - coefficient \: of \: x}{coefficient \: of \: \: \: {x}^{2} }

a + ( - a) = \frac{ - 4k}{1}

0 = -4k

0 = K

So, K = 0 !

Answer 2

Answer:

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Step-by-step explanation:

if a polynomial is (k-1)x2+kx+1

if one of the zeroes is -3

p(x)= (k-1)x2+kx+1

p(-3)=(k-1)(-3)^2+k(-3)+1=0

9k-9-3k+1=0

6k-8=0

6k=8

k=8/6

k=4/3