Question

if one zero of the quadratic polynomial (k-1)x²+kx+1 is -4, then the value of k is
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Answer 1

Answer:

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Answer 2

The value of k = 5/4

Given :

One zero of the quadratic polynomial (k - 1)x² + kx + 1 is - 4

To find :

The value of k

Solution :

Step 1 of 2 :

Write down the given polynomial

Here the given polynomial is (k - 1)x² + kx + 1

Step 2 of 2 :

Find the value of k

It is given that One zero of the quadratic polynomial (k - 1)x² + kx + 1 is - 4

This we get ,

$\displaystyle \sf{ (k - 1) \times {( - 4)}^{2} + k \times ( - 4) + 1 = 0}$

$\displaystyle \sf{ \implies 16(k - 1) - 4 k + 1 = 0}$

$\displaystyle \sf{ \implies 16k - 16 - 4 k + 1 = 0}$

$\displaystyle \sf{ \implies 12k - 15= 0}$

$\displaystyle \sf{ \implies 12k = 15}$

$\displaystyle \sf{ \implies k = \frac{15}{12} }$

$\displaystyle \sf{ \implies k = \frac{5}{4} }$

Hence the required value of k = 5/4

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