Question

If one zero of the quadratic polynomial (k-1)x2+kx+1 is 4 then find value of k​

Answer 1

Answer:

k=7/12

Step-by-step explanation:

x=4

(k-1) ×4×2+k×4+1

(k-1) 8+4k+1

8k-8+4k+1

12k-7

p(x) =0

12k-7=0

12k=7

k=7/12

Answer 2

$k = \frac{7}{2} \\ hope \: it \: helps \: u$