If one zero of the quadratic polynomial (k-1)x2+kx+1 is -4 then find value of k
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Answer:
Step-by-step explanation:
If one zero is -4 then
Substitute the value in the given equation such that the equation becomes zero
==> (k-1)(-4)^2 + k(-4) + 1 = 0
==> (k-1)(16) -4k + 1 = 0
==> 16k - 16 -4k +1 = 0
==> 12k -15 = 0
==> k = 15/12
==> k = 5/4
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