Question

If one zero of the quadratic polynomial (k + 3) x2 + kx + 3 is −2 find k

Answer 1

one zero is given. -2
then,
p(x)=(k+3)x^2+kx+3
p(-2)=(k+3)4-2k+3
0=4k+12+-2k+3
0=2k+15
2k=-15
k=-15/2

Answer 2

Step-by-step explanation:

GIVEN:-)

→ One zeros of quadratic polynomial = -3.

→ Quadratic polynomial = ( k - 1 )x² + kx + 1.

Solution:-

→ P(x) = ( k -1 )x² + kx + 1 = 0.

→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.

=> ( k - 1 ) × 9 -3k + 1 = 0.

=> 9k - 9 -3k + 1 = 0.

=> 6k - 8 = 0.

=> 6k = 8.

$\large \boxed{=> k = \frac{8}{6} = \frac{4}{3} }$

Hence, the value of ‘k’ is founded .