Question

If one zero of the quadratic polynomial p(x)=4x^2-8kx-9is negative of the other find the value of k

Answer 1

Hello friend,

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Question: If one zero of the quadratic polynomial p(x)=4x² - 8kx - 9 is negative of the other find the value of k.

Solution:

Let the roots be $\alpha$ and $- \alpha$ .

$ax^2 + bx + c = 4x^2 - 8kx -9$

a = 4

b = -8k

c = -9

Sum of roots = $\frac{-b}{a}$

$\alpha - \alpha$ = $\frac {8k}{4}$

0 = 2k

k = 0

Answer : k = 0

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Hope this helped you !!

Answer 2

Explanation:

Answer :- -----

→ k = 0 .

Step-by-step explanation :-

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

•°• k = 0 .

Hence, it is solved.