Question

if one zero of the quadratic polynomial P (Y) = 5y^2 + 13y + m is reciprocal of the other , then find the value of m.

Answer 1

p[y]= 5y^2+13y+m
        -2+5y+13y+m
   m=-2+18
   m=14
the value of m is 14

Answer 2

Answer:

Value of m is 5.

Step-by-step explanation:

Given that if one zero of the quadratic polynomial $P (Y) = 5y^2 + 13y + m$ is reciprocal of the other.

we have to find the value of m.

As, given one zero is reciprocal of other,

$\text{Let one be x therefore other is }\frac{1}{x}$

$\text{The general quadratic equation is }ax^2+bx+c=0$

$\text{The formula to find the product of zeroes is }\frac{c}{a}$

Polynomial: $P (Y) = 5y^2 + 13y + m$

$\text{Product of zeroes= }\frac{c}{a}=\frac{m}{5}$

$x.(\frac{1}{x})=\frac{m}{5}$

$m=5$

Hence, value of m is 5.