Question

if one zero of the quadratic polynomial x^2+3k+k is 2 then the value of k is?​

Answer 1

Answer:

Putting the value of x as 2

2²+3k+k=0

4+4k=0

4k=-4

k=-4/4

k=-1

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Answer 2

Let the given quadratic polynomial be :

p(x) = x2 + 3k + k Given one of the zero of the quadratic polynomial is 2.

Then, p(2) = 0 Put x = 2

in p(x), we get p(2) = (2)^2 + 3k + k = 0

=> 4 + 4k=0

4k= –4

k= –4/4

∴ k = –1