Question

if one zero of the quadratic polynomial x^2 +3x+k is 2. Then find the value of K. solve it with verification ​

Answer 1

Answer:

k = -10

Step-by-step explanation:

x = 2

p(x) = (2)^2 +3(2) + k

    = 4+6+k

   = 10 + k

p(x) = 0

therefore ;

10 + k =0

k = -10

Answer 2

Step-by-step explanation:

verification

${x}^{2} + 3x - 10 \\ \ {x}^{2} + 5x - 2x \times - 10 \\( x + 5)( x - 2) \\ x + 5 = 0 \\ x = - 5 \\ x - 2 = 0 \\ x = 2$

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