Question

if one zero of the quadratic polynomial x^2 +3x+k is 2. Then find the value of K. solve it with ✔Verification. ​

Answer 1

Answer:

k=-10

Step-by-step explanation:

x^2 + 3x + k

2^2 + 3(2) + k = 0

4 + 6 + k = 0

10 + k = 0

k = -10

Answer 2

${\blue{\underline{\underline{\bold{\huge{Given:-}}}}}}$

▪ P (x) = x^2 +3x +K

&

▪ One zero = 2

✏ We have to find out the value of K.

${\blue{\underline{\underline{\bold{\huge{Solution:-}}}}}}$

According to the question____

( x-2) is a factor of given polynomial.

Now, put the value of x in the given polynomial.

p(x) = x^2 +3x +K

➱ 2^2 + 3*2 + K =0

➱ K =-10

Hence, the value of K is ☞ -10.

$\huge\mathcal\color{teal} Verification :-$

x^2 +3x -10 =0

➯ x^2 -2x +5x -10 =0

➯ ( x+5) (x-2) =0

➯ x = 5 or -2

Hence, (verified)

Therefore , the value of K is -10.

${\huge{\mathcal{\tt{Hope \ It \ Helps..!!!}}}}$