Question

If one zero of the quadratic polynomial x2 + 3x + k is 2, then prove that k=-10​

Answer 1

Answer:

$x { }^{2} + 3x + k = 0 \\ (2) {}^{2} + 3(2) + k = 0 \\ 4 + 6 + k = 0 \\ 10 + k = 0$

$\huge{\mathcal{\boxed{\orange{k=-10}}}}$

✔hence proved

Answer 2

Step-by-step explanation:

zero of the polynomial=0

x-2=0

x=2

x2+3x+k=0

2^2+3*2+k=0

4+6+k=0

10+k=0

k=0-10

k=-10