Question

If one zero of the quadratic polynomial x2

+ 3x + k is 2, then find the value of k​

Answer 1

if one of the zero is x+2 =0

x = -2

x^2 + 3x +k = 0

(-2)^2 + 3(-2) + k = 0

4 -6 + k =0

k = 2

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Answer 2

The zero is 2

therefore put the value of 2 in place of x in the polynomial.

x^2 + 3x+k

2^2 + 3(2) + k = 0

4+6 +k = 0

10+k = 0

k = -10

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