Question

. If one zero of the quadratic polynomial x2+3x+k is 2, then the value of k is
(a) 10 (b)-10 (c)-7 (d)-2​

Answer 1

sum of roots=-3

2+a=-3

a=-5

product of roots =k

2×-5=k

k=-10

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Answer 2

Answer:

☞ Given , zero oF the polynomial = 2

and

☞ The polynomial = x^2 + 3x + k

so

$x ^{2} + 3x + k = 0 \\ \\ = > (2) ^{2} + 3(2) + k = 0 \\ \\ = > 4 + 6 + k = 0 \\ \\ = > 10 + k = 0 \\ \\ = > k = - 10$

⛄ So option (b) = - 10 iS correct ⛄

hope it helps uH ☺