Math, asked by vandanaxc4504, 19 days ago

If one zero of the quadratic polynomial x2 + 3x + k is 2, then the value of ‘k’ is

Answers

Answered by tennetiraj86
4

Step-by-step explanation:

Given :-

One zero of the quadratic polynomial

x²+3x+k is 2

To find :-

The value of k ?

Solution :-

Method-1:-

Given quadratic polynomial is x²+3x+k

Let P(x) = x²+3x+k

On comparing this with the standard quadratic polynomial ax²+bx+c then

a = 1

b = 3

c = k

One of the zeroes = 2

Let the another zero be A

We know that

Sum of the zeroes = -b/a

=> 2+A = -3/1

=> 2+A = -3

=> A = -3-2

=> A = -5 --------(1)

Therefore, Other zero = -5

We know that

Product of the zeroes = c/a

=> 2×A = k/1

=> 2×A = k

=> 2×-5 = k

=> -10 = k

Therefore, k = -10

Method -2:-

Given quadratic polynomial is x²+3x+k

Let P(x) = x²+3x+k

One of the zeroes = 2

We know that

If 2 is a zero then it satisfies the given polynomial P(x) i.e. P(2) = 0

=> P(2) = 2²+3(2)+k = 0

=> 4+6+k = 0

=> 10+k = 0

=> k = 0-10

=> k = -10

Therefore, k = -10

Answer :-

The value of k for the given problem is -10

Check:-

If k = -10 then the given polynomial will be x²+3x-10

=> x²+5x-2x-10

=> x(x+5)-2(x+5)

=> (x+5)(x-2)

To get zeroes of the polynomial P(x) then we write P(x) = 0

=> (x+5)(x-2) = 0

=> x+5 = 0 or x-2 = 0

=> x = -5 or x = 2

The zeroes are -5 and 2

One of the zeroes of P(x) is 2

Verified the given relations in the given problem.

Used formulae:-

The standard quadratic polynomial is ax²+bx+c

Sum of the zeroes = -b/a

Product of the zeroes = c/a

We can write P(x) = 0 to get the zeroes of P(x)

If a real number k is a zero of the polynomial P(x) then it satisfies the given polynomial i.e.P(k) = 0

Answered by kvalli8519
1

K = -10

Step-by-step explanation:

Given :

P(x) = x² + 3x + k

One zero(α) = 2

To Find :

Value of k .

Solution :

As, Sum of zeros = α + β = -b/a

⇒ 2 + β = -3/1

⇒ β = -3 - 2 = -5

  • Other zero (β) = -5

then, as Product of zeros = αβ = c/a

⇒ 2(-5) = k/1

⇒ -10 = k

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FINAL ANSWER :

value of k is -10 .

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