Question

If one zero of the quadratic polynomial x²-7x+5k is (-2), then find the value of k.

Answer 1

Answer :

The given polynomial is

f(x) = x² - 7x + 5k

Since (-2) is a zero of f(x),

f(-2) = 0

⇰ (-2)² - 7(-2) + 5k = 0

⇰ 4 + 14 + 5k = 0

⇰ 5k = - 18

⇰ k = - 18/5

∴ The value of k is (- 18/5)

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Answer 2

Answer:

The value of k is -18/5 for the quadratic polynomial x²-7x+5k with one of its zero as -2.

Step-by-step explanation:

Quadratic polynomial:

• The quadratic polynomial is a second degree polynomial and it has the highest degree as 2.

 Given polynomial is x²-7x+5k

• Let f(x) = x²-7x+5k

  and also (-2) is one of the zero of the given polynomial then f(-2)=0

          f(-2) =0

        (-2)²-7(-2)+5k = 0

                4+14+5k = 0

                    18+5k = 0

                         5k = -18

                           k = -18/5

          The value of k = -18/5

Know more about Quadratic equations:

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