if one zero of the quadratic polynomial xsquare plus x minus 2 is minus 2, find the other zero frnds pls can anyone help me out this
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Answered by
5
Hey there!
Down here ⏬
p(x) = x {}^{2} + x - 2p(x)=x2+x−2
Since, -2 is the zero of p(x), (x+2) is a factor of p(x)
✓ Divide p(x) by (x+2)
{ By long division, refer attachment)
✓ x-1 is the qouteint obtained.
x - 1 = 0x−1=0
x = 1x=1
Therefore, 1 is the other zero.
Hope helped.
Down here ⏬
p(x) = x {}^{2} + x - 2p(x)=x2+x−2
Since, -2 is the zero of p(x), (x+2) is a factor of p(x)
✓ Divide p(x) by (x+2)
{ By long division, refer attachment)
✓ x-1 is the qouteint obtained.
x - 1 = 0x−1=0
x = 1x=1
Therefore, 1 is the other zero.
Hope helped.
Attachments:
cloudboy55:
sinaan
ok
where to send the question
U have anything private like Insta or something
no...
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now wt to do
U ask the question in brainy and follow me so I can see the question ur asking
ok bye
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Answered by
0
Answer:
Hey there!
Down here ⏬
p(x) = x {}^{2} + x - 2p(x)=x
2
+x−2
Since, -2 is the zero of p(x), (x+2) is a factor of p(x)
✓ Divide p(x) by (x+2)
{ By long division, refer attachment)
✓ x-1 is the qouteint obtained.
x - 1 = 0x−1=0
x = 1x=1
Therefore, 1 is the other zero.
Hope helped.
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