Question

If one zero of the quadratic polynomial4x^2-8kx-9 is negative of the other find the balue of k

Answer 1

Hey!

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[ @ = Alpha , ß = Beta ]

Let @ and ß be zeroes if the polynomial 4x^2 - 8kx - 9

a = 4 , b = -8k, c = -9

A.T.Q
@ = - ß
That means, @ + ß = 0

[ We know sum of zeroes = -b/a ]

@ + ß = 0

-b/a = 0

-8k/4 = 0

-2k = 0

k = 0


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Hope it helps...!!!

Answer 2

$Hey \: There$!!
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$p(x) = {4}^{2} - 8kx - 9$

$Let \: the \: zeroes \: of \: given \: polynomial \: be \: \alpha \: and \: \beta .$
$A.T.Q.$
$\alpha = - \beta$
$\alpha + \beta = 0$

$We \: know \: that,$
$Sum \: of \: zeroes = \frac{ - b}{a}$
$\alpha + \beta = \frac{ - b}{a}$
$0 = \frac{ - b}{a}$
$0 = \frac{ - 8k}{4}$
$- 8k = 0$
$k = 0$
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$Hope \: my \: ans.'s \: satisfactory.$