Question

If one zero of x^2 - 4x + 1 is 2 + 3^-1, write the other zero.​

Answer 1

Answer:

x²-4x+1

here, a=1,b=-4,c= 1

1st zero = 2+3^-1

= 2+(1/3)

= 6/3+1/3

= 7/3

sum of zeroes = -b/a

= -(-4)/1

= 4

2nd zero = 4-(7/3)

= 12/3-7/3

= 5/3

ans.

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