Question

if one zero of x^2-(a+1)x+6 is 3 then a is

Answer 1

hey!

if 3 is a zero of x^2-(a+1)x+6
then, put x=3
and 3^2-(a+1)3+6=0
9-3a-3+6=0
6+6+3a=0
12+3a=0
3a=12
a=12/3=4

hope it helps!!

Answer 2

Let the other root be alpha (x)
So,
a+1=3+x
and
-6=3×x
So, x=-2
So, a=0
a=0