Question

if one zero polynomial a square + 9 into X square + 13 x + 6a is reciprocal of the Other find the value of a

Answer 1

........................

Answer 2

(a^2+9)x^2+13x+6a

Here a= a^2+9, b= 13,c= 6a

Let one zero of polynomial is = x

And another zero of the polynomial is = y

Product of zeroes= c/a

x*1/x = 6a/a^2+9

1 = 6a/a^2+9

a^2+9 = 6a

a^2+9-62 = 0

a^2-3a-3a+9 = 0

a(a-3)-3(a-3) = 0

(a-3) (a-3) = 0

a = 3