Question

If one zeroes of the polynomial (k-1)x²+kx+1 is -3.What is the value of k

Answer 1

Answer:

Remainder Theorem:

p(x) = (k-1)x²+kx+1

p(-3) = 9(k-1) -3k+1

0 = 9(k-1) -3k+1

-1 = 9k -9 -3k

9 = 6k

k = 9/6 = 3/2

Answer 2

Answer:

answer is 1.1

hope it will help you