Question

If one zeroes of the polynomial p(x) = x^2+a is-5 find the value of a and other zero

Answer 1

Answer:

Step-by-step explanation:

p(x) = x²+a

p(-5) = (-5)² + a = 0

        = 25 + a =0

        = a = - 25

so the value of a = -25

now x²-25=0

   x² - (5)² = 0

(x+5)(x-5) = 0

x = -5 and 5