Question

if one zeroof the quadratic polynomial
$4 {x }^{2} - 8kx - 9$
is negative of the other find the value of k​

Answer 1

HERE IS YOUR ANSWER MATE.....;

$= > 4x {}^{2} - 8kx - 9$

ONE ZERO => X

OTHER ZERO => -X

$sum \: of \: zeroes \: = \frac{ - b}{a}$

$= > x - x = - \frac{( - 8k)}{4}$

$= > 0 = + 8k$

$= > k = 0$

HOPE IT'S HELPFUL.....:-)

Answer 2

Answer:

Step-by-step explanation:

ONE ZERO => X

OTHER ZERO => -X

sum \: of \: zeroes \:  =  \frac{ - b}{a}  

 =  > x - x =  -  \frac{( - 8k)}{4}  

 =  > 0 =  + 8k

 =  > k = 0