Question

If one zeros of polynomial (a+9)x²+13x+6a is a reciprocal of other, find the value of a​

Answer 1

Answer:

Step-by-step explanation:

(a+9)x²+13x+6a

a=(a+9), b=13, c=6a

let the zeroes be α and β

ACCORDING TO THE QUESTION

α=1/B

αβ=1  (1)

αβ=c/a  (2)

1=6a/a+9

a+9=6a

9=6a-a

9=5a

9/5=a

1.8=a