Math, asked by birthday569, 1 year ago

If one zeros of quadratic polynomial 2x^2+px+4 is 2.find the other zeros.find the value p

Answers

Answered by Panzer786
10
Hey !!




P ( X ) = 2X² + PX + 4


Substitute X = 2 in P ( X ).



P (2) = 2 × (2)² + P × 2 + 4



=> 2 × 4 + 2P + 4 = 0


=> 8 + 2P + 4 = 0



=> 2P + 12 = 0



=> 2P = -12


=> P = -6
Answered by RohitSaketi
5
Given quadratic polynomial is 2x^2+px+4 ...(1)

One of the zeroes is 2 ..

subsitute it in equation (1)

2x^2+px+4 = 0

2(2)^2+p(2)+4=0

2(4) + p(2) + 4 = 0

8+2p+4=0

12+2p =0

2p = -12

p=-12/2

p=-6..

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