Question

if one zeros of the quad . polynomial x^2-5x+k is -4 find k​

Answer 1

Explanation:

this is your answer dear

plzzz mark me as brainliest plzzzzz

Answer 2

${ \huge{ \underline{ \underline{ \sf{ \green{GivEn : }}}}}}$

• f(x) = x² - 5x + k

• One zero = - 4

${ \huge{ \underline{ \underline{ \sf{ \green{To \: find :}}}}}}$

• value of k

${ \huge{ \underline{ \underline{ \sf{ \green{SoluTion : }}}}}}$

A quadratic polynomial is given as:-

⠀⠀⠀⠀p(x) = x² - 5x + k

Where, one zero of the polynomial is = - 4

Now, put x = - 4 in the polynomial to find the value of k.

⠀⟼ (-4)² - (5 × -4) + k = 0

⠀ ⟼ 16 + 20 + k = 0

⠀⠀⟼ 36 + k = 0

⠀⠀⟼ k = -36

Hence, value of k is = -36

__________________________________________________

Verification :-

⟶ x² - 5x - 36 =0

( Putting k = -36)

⟶ x² + 4x - 9x - 36 = 0

⟶ x(x + 4)-9(x + 4) = 0

⟶ (x + 4)(x - 9) = 0

⟶ x = -4 and x = 9

Hence, one zero of the polynomial is = -4 .

(Verified)