Question

if onre zero of the polynomial 2x^2+3x+k is 1/2, find the value of k and other zero ​

Answer 1

Answer:

k=2/5 is the answer of this question

Answer 2

Answer:

k= -4/2 = -2

Step-by-step explanation:

$p(x) = {2x}^{2} + 3x + k \\ \alpha = \frac{1}{2} \\ put \: in \: p(x) \\ p(x) = 0 \\ 2x {}^{2} + 3x + k = 0 \\ 2( \frac{1}{2} ) {}^{2} + 3( \frac{1}{2} ) + k = 0 \\ (2 \times \frac{1}{4} ) + ( \frac{3}{2} )+ k = 0 \\ \frac{1}{2} + (\frac{3}{2} ) + k = 0 \\ \frac{1 + 3}{2} + k = 0 \\ k = - \frac{4}{2}$

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