Question

if or an A.P.,t2=4 and d= -2, then waht is the value of a​

Answer 1

given

t2=4

d=-2

a=?

we have

d=t2-a

-2=4-a

-a=-6

a=6

hope it will help

Answer 2

Solution

$t _{2} = 4 \: and \: common \: difference \: d = - 2$

To find, the term(a)=?

___________________

We know that,

$a_{n} = a + (n - 1)d$

$:. a_{n} = a + (2 - 1)d$

$= > a + d = 4$

$a - 2 = 4$

$a = 4 + 2 = 6$

Hence, the value of a is"6"