If order of a is m and order of b is n and group is ableian, then order of (ab)?
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a) am=eam=e, bn=ebn=e , which follows amn=eamn=e, bmn=ebmn=e. Since G is abelian, (ab)mn=amnbmn=e(ab)mn=amnbmn=e.
for b i know it somthing related to gcd(m,n) and lcm(m,n) but i dont know hot to start the prove
and i think the the solution of b is the begining of the solution of c.
a) am=eam=e, bn=ebn=e , which follows amn=eamn=e, bmn=ebmn=e. Since G is abelian, (ab)mn=amnbmn=e(ab)mn=amnbmn=e.
for b i know it somthing related to gcd(m,n) and lcm(m,n) but i dont know hot to start the prove
and i think the the solution of b is the begining of the solution of c.
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