if order of a matrix A is m×n then order of a matrix B is l×n then what is the order of matrix ab?
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Step-by-step explanation:
m*n
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Since n~columns of B = n ~ rows of A, .’. BA exists. And the size of BA=mxp.. Then compute AB by multiplying the first row of B with the first column of A to get the first entry of BA , then the first row of B with the second column of A to get the second entry of BA, do this until the the you multiply the first row of B with the nth column of A. Then repeat all the same procedure until you multiply the nth row of B with the mth columns of A then you get your last entry of BA.
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