Question

If order of g is pq, then g is cyclic proof it

Answer 1

Step-by-step explanation:

Proof of G is a cyclic group with |G|=|pq|

Then G is cyclic. In the proof they are saying, that when n is the number of all Sylow q-subgroups and m is the number of all Sylow p-subgroups, then n divides pq and q divides n−1. Also m divides pq and p divides m−1. Since p<q we conclude that n=1.