Question

If origin and (3,2) contained in the same angle of the lines 2x+y-a=0 , x-3y+a=0 than a must be in the interval

Answer 1

$\textbf{Heya}$

Origin :-

Coordinates = (0,0)

x = 0, y = 0

2x + y - a = 0

2(0) + 0 - a = 0

-a = 0

a = 0

Point A

Coordinates = (3,2)

x = 3, y = 2

x - 3y + a = 0

3 - 3(2) + a = 0

3 - 6 + a = 0

-3 + a = 0

a = 3

So,

the value of a will lie between $\textbf{0 and 3}$

$\textbf{Hope this helps you.}$

Answer 2

Answer:

between o and 3

Step-by-step explanation: