if origin is the centroid of the triangle abc with vertices a (a,1,3 ), b(-2, b,-5) and c (4,7, c) then values a, b, c
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Centroid of the triangle=(0,0,0) =(a-2+4/3,1+b+7/3,3-5+c/3) =>a+2=0=>a= -2 .=>
8+b=0=>b= -8. =>c-2=0=> c=2. it is done by using the formula centroid of a triangle with vertices A(a,b,c) ,B(x,y,z)and C(p,q,r)=(a+x+p/3,b+y+q/3, c+z+r/3) . Hope it helps you...
8+b=0=>b= -8. =>c-2=0=> c=2. it is done by using the formula centroid of a triangle with vertices A(a,b,c) ,B(x,y,z)and C(p,q,r)=(a+x+p/3,b+y+q/3, c+z+r/3) . Hope it helps you...
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