Question

if our genius then solve this math Q it simple ( you have 100 rupees and you purchase 100 animal in 100 rupees) animal 1 goat = ₹1 , 1 elephant=₹ 5,1camil=₹20. I have answer​ But all animals type is there in answer​

Answer 1

Answer:

How do I purchase 100 animals in Rs 100? Where 1 horse is Rs 1, 1 elephant is Rs 5, and 20 camels are Rs 1?

Suppose that number of horses is x, number of elephants is y and number of camels is z.

prices are:

1 horse = Rs 1

1 elephnat = Rs 2

20 camels = Rs 1 means 1 camel = Rs 0.05.

we can form two equations:

total number of animals = 100

x+y+z = 100 …………….(1)

and total sum of money = 100

1x + 5y + 0.05z = 100 …………(2)

by equations (1) and (2)

-4y + 0.95z =0

.95z = 4y

z/y = 4/0.95

z/y = 80/19 (after simplification )

so if z(camels) = 80 and y(elephants) = 19

then horses,x = 100-y-z ( from equation 1)

x= 100–80–19

x=1

now

1 horse = Rs 1

19 elephnats = 19*5= Rs 95

80 camels = 80*0.05 = Rs 4

Note : The system of equations in this question has infinite solutions like x=50.5; y=9.5 and z=40, and x= -18; y= 38 and z=80, but in our question we need natural numbers values for x y and z, So only one solution satisfies our condition.

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

Suppose that number of horses is x, number of elephants is y and number of camels is z.

prices are:

1 horse = Rs 1

1 elephnat = Rs 2

20 camels = Rs 1 means 1 camel = Rs 0.05.

we can form two equations:

total number of animals = 100

x+y+z = 100 …………….(1)

and total sum of money = 100

1x + 5y + 0.05z = 100 …………(2)

by equations (1) and (2)

-4y + 0.95z =0

.95z = 4y

z/y = 4/0.95

z/y = 80/19 (after simplification )

so if z(camels) = 80 and y(elephants) = 19

then horses,x = 100-y-z ( from equation 1)

x= 100–80–19

x=1

now

1 horse = Rs 1

19 elephnats = 19*5= Rs 95

80 camels = 80*0.05 = Rs 4

Note : The system of equations in this question has infinite solutions like x=50.5; y=9.5 and z=40, and x= -18; y= 38 and z=80, but in our question we need natural numbers values for x y and z, So only one solution satisfies our condition.