If p(0,0) ,q(2,b) ,r(a,4) and s(4,4) are vertices of a parallelogram pqrs .Find value of a and b
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we know diagonal of a parallelogram bisect each other
therefore
(0+a/2 , 0+4/2)=(2+4/2 , b+4/2)
(a/2,2)=(3,b+4/2)
Now
a=6
b=0
therefore
(0+a/2 , 0+4/2)=(2+4/2 , b+4/2)
(a/2,2)=(3,b+4/2)
Now
a=6
b=0
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