Question

if P (0, 6),Q(-5, 3) and R (3, 1) are the vertices ∆PQR, what kind of triangle is PQR​

Answer 1

Answer:

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Step-by-step explanation:

FOR:

(X1, Y1) = (0, 6)

(X2, Y2) = (-5, 3)

distance between PQ

d=√(−5−0)^2+(3−6)^2

d=√(−5)^2+(−3)^2

d=√25+9

d=√34

FOR:

(X1, Y1) = (-5, 3)

(X2, Y2) = (3, 1)

distance between QR

d=√(3−(−5))^2+(1−3)^2

d=√(8)^2+(−2)^2

d=√64+4

d=√68

FOR:

(X1, Y1) = (3, 1)

(X2, Y2) = (0, 6)

distance between RP

d=√(0−3)^2+(6−1)^2

d=√(−3)^2+(5)^2

d=√9+25

d=√34

as you can see that distance of RP and PQ is same. therefore triangle PQR is an isosceles triangle