Question

if p =0 and q=3 then p + pq+q²​

Answer 1

Answer:

=0+0*3+0^2 (value given)

=0+0+0

=0 Ans.

Answer 2

Answer:

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$\huge\bold\underline {According \: to \: Question}$

$p = 0$

$q = 3$

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Putting the values in equation p + pq+q², we get:-

$= > p + pq + {q}^{2}$

$= > 0 + 3 \times 0 + {3}^{2}$

$= > 0 + 0 + 9$

$= > 9$

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$\tt {Additional \: Identities }$

$( {x + y})^{2} = {x}^{2} + {y}^{2} + 2xy$

$( {x - y})^{2} = {x}^{2} + {y}^{2} - 2xy$

${x}^{2} - {y}^{2} = (x + y)(x - y)$

$(x + a)(x - b) = {x}^{2} + (a + b)x + ab$

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