Question

If p(0)=x^2+5×+6 then find p(0),p(1),p(2),p(3)

Answer 1

p(0)=6

p(1)=12

p(2)=20

p(3)=30

Answer 2

The values of p(0), p(1), p(2) and p(3) will be "6", "12", "20" and "30". Further explanation is given below.

Step-by-step explanation:

Given:

p(0)= x²+5x+6

Now, on putting "0", "1", "2" and "3" in place of "x" we get,

⇒ p(0) = (0)²+5×0+6

⇒         = 0+0+6

⇒         = 6

⇒ p(1) = (1)²+5×1+6

⇒        = 1+5+6

⇒        = 12

⇒ p(2) = (2)²+5×2+6

⇒         = 4+10+6

⇒         = 10+10

⇒         = 20

⇒ p(3) = (3²)+5×3+6

⇒         = 9+15+6

⇒         = 30

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