if P = { 1,2,5,7,9} , Q = { 2,3,5,9,11 } , R = { 3,4,5,7,9 } and S = { 2,3,4,5,8 } , then find ii ) ( p intersection Q ) intersection S
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Given P={1,2,5,7,9}
Q={2,3,5,9,11}
R={3,4,4,7,9}
S={2,3,4,5,8}
P intersection Q=all elements that are common between P and Q={2,5,9}
Now let p intersection Q be set X
Implies that X intersection S =all elements that are common between X & S= {2,5}
Hence answer =(p intersection q) intersection s
= {2,5}
If there is any problem with my solution please let me know
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