If p=(-1)^205 and q=(-1)^202 then find p+q?
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Answered by
4
p=(-1)^205, q=(-1)^202
(-1)^even=1.
(-1)^odd=-1.
p=-1, q=1.
p+q=-1+1.
p+q=0.
(-1)^even=1.
(-1)^odd=-1.
p=-1, q=1.
p+q=-1+1.
p+q=0.
Answered by
5
-1 = -1
-1 = 1
p+q= -1 + 1
= 0 is your answer
-1 = 1
p+q= -1 + 1
= 0 is your answer
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