If p = 1/3 (6p+12), then the value 1 point of p is ?
Answers
Answered by
0
Answer:
=p=1
Step-by-step explanation:
For collinearity of points A(−1,3),B(2,p),C(5,−1), area of ΔABC should be zero ,i.,e,
2
1
∣(p−1)+2(−1−3)+5(3−p)∣=0
⇒p−1−8+15−5p=0
⇒−6p+6=0
⇒−6p=−6
⇒p=1
Similar questions